Question

if a+b+c=0 then a³+b³+c³​

Answer 1

Answer:

hope it helps ☺️

please mark the answer as brainliest

follow me to get the answers to your questions....

Step-by-step explanation:

If a + b + c = 0 then, a³ + b³ + c³ = 3abc

∵ a³ + b³ + c³ – 3abc = (a + b + c) (a² + b² + c² – ab – bc – ac)

Answer 2

$\star\underline{\mathtt\orange{⫷❥Q᭄} \mathfrak\blue{u~ }\mathfrak\blue{Σ} \mathbb\purple{ §}\mathtt\orange{T} \mathbb?\pink{iOn⫸}}\star\:$

if a+b+c=0 then a³+b³+c³

$\star\underbrace{\mathtt\red{⫷❥ᴀ᭄} \mathtt\green{n~ }\mathtt\blue{ §} \mathtt\purple{₩}\mathtt\orange{Σ} \mathtt\pink{R⫸}}\star\:$

$\bold\star\mathtt{\fcolorbox{red}{pink}{GiVeN}}$

$a+b+c=0$

$\bold\star\mathtt{\fcolorbox{red}{pink}{To\:PrOvE}}$

$a³+b³+c³=?$

${ \color{aqua}{ \underbrace{ \underline{ \color{lime}{ \mathbb{✯꧁ ⋆᭄ SoLuTiOn⋆᭄꧂✯ }}}}}}$

$formula =$

${a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)$

$a + b + c = 0$

${a}^{3} + {b}^{3} + {c}^{3} - 3abc = (0)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)$

${a}^{3} + {b}^{3} + {c}^{3} - 3abc = 0$

${a}^{3} + {b}^{3} + {c}^{3} = 3abc$

$\blue{\boxed{\blue{ \bold{\fcolorbox{red}{black}{\green{☺︎︎Hope\:It\:Helps☺︎︎}}}}}}$

${\mathbb{\colorbox {orange} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {lime} {\boxed{\boxed{\boxed{\boxed{\boxed{\colorbox {aqua} {@suraj5069}}}}}}}}}}}}}}}$