If a + b + c = 0, then a3 + b3 + c3 – 3ab = …………………………….
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By assumption a^3+b^3+c^3=3abc
so the left hand side is 0. ...
Therefore (a-b)^2 + (b-c)^2 + (c-a)^2 =0 so
a=b=c.
So either a+b+c=0 or a=b=c.
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