if (a+b+c)=0 then (a³+B³+c³) is
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→ a + b + c = 0. → a³ + b³ + c³ . → a³ + b³ + c³ - 3abc = ( a + b + c ) ( a²+ b² + c² - ab - bc - ca ). ... => a³ + b³ + c³ - 3abc = 0.
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in this image 1st one have half answer and second look gave remaining have
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