If (a+b+c)=0 then (a³+B³+c³) is
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0 is the right answer.
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since \: {a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - bc - ca - ab)
Given, a+b+c=0
∴a3+b3+c3−3abc=0
∴a3+b3+c3=3abc
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