If a + b + c = 0, then a³ + b³ + c³ is equal to
0
abc
3abc
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a³ + b³ + c³ -3abc = (a+b+c)(a²+b²+c²+2ab+2bc+2ca)
a³+b³+c³ -3abc = (0)( a²+b²+c²+2ab+2bc+2ca)
a³+b³+c³-3abc = 0
a³+b+c³ = 3abc
Answer is 3abc
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