If a+b+c=0. then (a⁴+b⁴+c⁴)/(a²b² + b²c² +c²a²) is equal to
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a+b+c=0
⇒a+b=−c
⇒(a+b)2
=(−c) 2
⇒a2+b2+2ab=c2
⇒a2+b2-c2=-2ab
⇒(a2+b2-c2)2=(-2ab)2
⇒a4+b4+c4+2a 2b2-2b3c
22-2a2 −2b c 2 −2a 2c 2=4a 2b 2
⇒a 4+b 4+c 4=2a 2 b 2+2b 2c 2+2a 2c 2
⇒ a 2 b 2 +b 2 c 2 +a 2 c 2a 4+b 4 +c 4 =2
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