If a+b+c=0,then ab(a+b)+bc(b+c)+ca(a+c)+3abc=?
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given
a+b+c = 0
ab (-c)+bc (-a)+ca (-b)+3abc
= -abc-abc-abc+3abc
=-3abc+3abc
=0
a+b+c = 0
ab (-c)+bc (-a)+ca (-b)+3abc
= -abc-abc-abc+3abc
=-3abc+3abc
=0
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