If a+b+c=0 then b^2+c^2+a^2/b^2-ca
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7
Answer:
refer to the attachment
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Answered by
2
Answer:
a+b+c=0
a=−b−c .
(a+b+c)
2
=0
a
2
+b
2
+c
2
+2(ab+bc+ca)=0
K(a
2
−bc)+2(ab+bc+ca)=0
2(ab+bc+ca)=−K(a(−b−c)−bc)
⟹2(ab+bc+ca)=K(ab+bc+ca)
⟹K=2
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