if a+b+c=0 then determine one zero of p(x)=ax2 +bc+c
Answers
Answered by
0
Step-by-step explanation:
f(x)=ax2+bx+c
f(1)=a+b+c=0
That makes x−1 a factor, so
f(x)=(x−1)(ax−c)
where ax and −c are the factors that make the first and last term work out. We check the middle term, noting b=−(a+c).
(x−1)(ax−c)=ax2−(a+c)x+c=ax2+bx+c✓
(x−1)(ax−c)=0 means
Answer: x=1 or x=c/a
Similar questions