Question

If a+b+c=0 , then evaluate a3+b3+c3

Answer 1

if a+b+c=0 then,
a^3+b^3+c^3=(ab+bc+ca)is the ans

Answer 2

) Now, a3+b3 + c3 = (a+ b + c) (a2 + b2 + c2 – ab – be – ca) + 3abc

[using identity, a3+b3 + c3 – 3 abc = (a + b + c)(a2+b2+c2 –ab–bc-ca)] = 0 + 3abc [∴ a + b + c = 0]

a3+b3 + c3 = 3abc.