If a+b+c=0 then find a^2/bc + b^2/ca -3=0
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a²/bc +b²/ca -3,LCM lend per
=>(a³+b³)/abc -3
(a³+b³-3abc)/abc, ( a³+b³-3abc)formula hai
(a+b+c)(a²+b²+c²-ab-bc-ca)/abc
(0)×(......)/abc=0
=>(a³+b³)/abc -3
(a³+b³-3abc)/abc, ( a³+b³-3abc)formula hai
(a+b+c)(a²+b²+c²-ab-bc-ca)/abc
(0)×(......)/abc=0
Thanks a lot
Will u please explain the second and last step?
i hopes ,your will be understand
Okayy
But thanks a lot.....
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