Question

If √a+√b+√c =0 then find (a+b+c )^2

Answer 1

Answer:

Given a+b+c=0

From that, a+b=-c, a+c=-b, b+c=-a

Next is follows,

=(a+b-c)³+(c+a-b)³+(b+c-a)³

=(-2c)³+(-2b)³+(-2a)³

=-8(a³+b³+c³)

=-8(3abc) [because, if a+b+c=0, a³+b³+c³=3abc]

=-24abc