Question

if a⅓+b⅓+c⅛=0 then find (a+b+c)³​

Answer 1

Answer:

Step-by-step explanation:

∵ a¹ʹ³ + b¹ʹ³ + c¹ʹ³ = 0

(a¹'³)³ + (b¹ʹ³)³ + (c¹ʹ³)³ = 3(a¹ʹ³) (b¹ʹ³) (c¹ʹ³)

a + b + c = 3 (abc)¹ʹ³

( a + b + c )³ = [ 3 (abc)¹ʹ³ ]³

( a + b + c )³ = 3³ [ (abc)¹ʹ³ ]³

( a + b + c )³ = 27abc

Answer 2

Answer:

the answer is (a+b+c)³=27abc

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