Question

if a+b+c=0 then find (a+b-c)³+(c+a-b)³+(b+c-a)³​

Answer 1

a+b+c = 0 (given)

Let a = -2, b = -2 and c = 4

Then, (a+b-c)³+ (c+a-b)³ + (b+c-a)³

          (-2-2-(4))³ + (4-2-(-2))³ + (-2+4-(-2))³

          (-2-2-4)³ + (4-2+2)³ + (-2+4+2)³

          (-8)³ + (4)³ + (4)³

          -512+64+64

          -512+128

          -384

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