Question

if a+b+c =0 then find the one of the eoots of quadratice equation ax^2+bx+c=0

Answer 1

ax2+bx+c=0ax2+bx+c=0 Sum of roots of this equation will be −ba−ba

as one root is 22 so we have 

4a+2b+c=04a+2b+c=0------------(1)

cx2+bx+a=0cx2+bx+a=0 as one root is −13−13

we have c9−b3+a=0=>9a−3b+c=0c9−b3+a=0=>9a−3b+c=0-------(2)

subtract equation (1) from (2) we get 5a−5b=0=>ba=15a−5b=0=>ba=1

so −ba=−1
hence ba=1.

Answer 2

root of the quadratic equation are gjvem by quadratuc formula.

which is
$- b + \frac{ \sqrt{ {b}^{2} - 4ac } }{2ab} \: and \: - b - \frac{ \sqrt{ {b }^{2} - 4ac }$