Question

If a+b+c =0 then find the value of (a+b)(b+c)(c+a)​

Answer 1

Answer: -abc

Step-by-step explanation:

a+b+c = 0

=> a + b = -c

Similarly b + c = -a

c + a = -b

Hence (a + b)(b + c)(c + a)

=> -a*-b*-c = -abc

Or you can do (a + b)(b + c)(c + a) = (a + b + c)(ab + bc + ca) - abc

Since (a + b + c) = 0 ,  (a + b + c)(ab + bc + ca) = 0

So the answer left is -abc .

Answer 2

Step-by-step explanation:

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