Question

if a+b+c=0,then find the value of (a+b-c)^3+(b+c-a)^3+(c+a-b)^3​

Answer 1

Step-by-step explanation:

So,

a+b=-c

Now, a+b-c= -c-c= -2c

b+c=-a

Now, b+c-a= -a -a = -2a

c+a= -b

Now, -b-b= -2b

So,

(-2c)^3+(-2b)^3+(-2a)^3

-8c^3-8b^3-8a^3