Question

If a+b+c=0 then find the value of a2/bc+b2/ca+c2/ab

Answer 1

Step-by-step explanation:

a+b+c =0

hence

a³+b³+c³=3abc(conditional identity)

a³+b³+c³=3abc

(divide ABC in all)

a³/ABC+b³/ABC+c³/ABC=3abc/ABC

(after cancellation)

a²/BC+b²/ac+c²/ab=3

Answer 2

Answer:

3

Step-by-step explanation:

a^3+b^3+c^3

[a+b+c] [a^2+b^2+c^2-ab-bc-ac]+3abc

[a+b+c] [a^2+b^2+c^2-ab-bc-ac]+3abc=a^2/bc+b^2/ca+c^2/ab

3abc

abc=3