if a+b+c=0 then find the value of a³+b³+c³
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Answered by
3
Step-by-step explanation:
a³+b³+c³=3abc
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Answered by
7
Given :-,
→ a + b + c = 0.
➡ To Find :-
→ a³ + b³ + c³ .
➡ Solution:-
▶ By using an identity :-
→ a³ + b³ + c³ - 3abc = ( a + b + c ) ( a²+ b² + c² - ab - bc - ca ).
Now, put the value of ( a + b + c ) in the identity.
=> a³ + b³ + c³ - 3abc = ( 0 ) ( a²+ b² + c² - ab - bc - ca ).
We know that if any number is multiplied by 0, then the value came out is 0.
→ Here, ( a²+ b² + c² - ab - bc - ca ) is the number.
→ So, it is multiplied by 0, then the value is 0.
=> a³ + b³ + c³ - 3abc = 0.
Move the - 3abc to the RHS side, the minus value changes to plus.
=> a³ + b³ + c³ = 3abc.
✔✔ Hence, it is solved ✅✅.
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