Question

If a+b+c=0 then find the value of (b+c)² be + (c+a)² ac + (a+b)² ab


<= 0.​

Answer 1

Answer:

A+b+c=0

1. b+c=-a

2. a+b=-c

3. c+a=-b

-a^3/bc + -b^3/ca + -c^3/ab

=-(a^3+b^3+c^3)/abc

=-3abc/abc

=-3

hope it helpful