Math, asked by logithavasanthi, 1 day ago

If a+b+c=0 then find the value of x^a+b-c x^b+c-a .x^c+a - b
a) 0
b) 1
c) x2​

Answers

Answered by shreyatiwari868
0

Answer:

b.)1

Step-by-step explanation:

Given:

a+b+c=0

We have to find the value of x^(a+b-c).x^(b+c-a).x^(c+a-b).

•For this let us simplify the powers,

since, a+b+c=0

Therefore, a+b=-c.................................(1)

b+c=-a..................................(2)

and, c+a=-b.................................(3)

•Now on substituting these values in the given expression we get,

x^(-c-c).x^(-a-a).x^(-b-b)= x^(-2c).x^(-2a).x^(-2b)

= x^(-2c-2a-2b)

=x^-2(a+b+c)

=x^-2(0) [since, a+b+c=0(given)]

=x^0

=1 (Answer).

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