If a+b+c=0 then find the value of x^a+b-c x^b+c-a .x^c+a - b
a) 0
b) 1
c) x2
d) 2
plz explain and say the answer i'll make u as brainlist
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Answer:
Given,
∣∣∣∣∣∣∣∣x+aaabx+bbccx+c∣∣∣∣∣∣∣∣
=(x+a)det(x+bbcx+c)−bdet(aacx+c)+cdet(aax+bb)
=(x+a)(x2+cx+bx)−b(ax)+c(−ax)
=x3+ax2+bx2+cx2
=x2(x+a+b+c)
=x2(0)=0
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