Question

if a-b-c= 0 then prof that, a²(b+c)+b²(c-a)+c²(b-a)=3abc

Answer 1

yes
°.° a-b-c= 0
a= b+c
-b=c-a
-c=b-a
.°. a²(b+c)+b²(c-a)+c²(b-a)
=a².a+b²(-b)+c²(-c)
=a³-b³-c³
=(a-b)³-3ab(a-b)-c³
=c³+3ab(c)-c³
=3abc
proved