If a+b+c=0,then prov that a^3+b^3+c^3=3abc
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maaankhan:
wrong.. because cubes cant be common as number to other side. (see last line)
see question, it is not 3ab. it is 3abc
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given a+b+c=0. ____(1)
a^3+b^3+c^3=3abc
using value of a,b,c =0 from (1)
0^3+0^3+0^3=3×0×0×0
by solving
0=0.
hence the value is equal .
so,
a^3+b^3+c^3=3abc
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