Math, asked by ikki6024, 10 months ago

If a+b+c=0,then prov that a^3+b^3+c^3=3abc

Answers

Answered by Anonymous
0

Please refer to the attached document

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maaankhan: wrong.. because cubes cant be common as number to other side. (see last line)
maaankhan: see question, it is not 3ab. it is 3abc
Answered by maaankhan
0

given a+b+c=0. ____(1)

a^3+b^3+c^3=3abc

using value of a,b,c =0 from (1)

0^3+0^3+0^3=3×0×0×0

by solving

0=0.

hence the value is equal .

so,

a^3+b^3+c^3=3abc

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