If a+b+c=0,then prove (b+c)(b-c)+a(a+2b)
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a+b+c=0
a+b= –c
squaring both sides
(a+b)^2 = (–c)^2
a^2 + b^2 + 2ab = c^2
b^2 – c^2 + a^2 + 2ab =0
(b+c)(b–c) +a(a+2b)=0
[H.P.]
a+b= –c
squaring both sides
(a+b)^2 = (–c)^2
a^2 + b^2 + 2ab = c^2
b^2 – c^2 + a^2 + 2ab =0
(b+c)(b–c) +a(a+2b)=0
[H.P.]
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