If a+b+c =0 then prove that (a^2/bc)+(b^2/ca)+(c^2/ab)=3
Answers
Answered by
6
hii mate...
Given a + b + c = 0
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 [From (1)]
Given a + b + c = 0
⇒ a3 + b3 + c3 = 3abc → (1)
Consider, (a2/bc) + (b2/ca) + (c2/ab)
= (a3 + b3 + c3)/abc
= 3abc/abc = 3 [From (1)]
itachi41:
hi
hii
in which class are you
Answered by
4
here is your answer
please.ark as brain liest
the lines I have cut are not part of answer so please see before writing
please.ark as brain liest
the lines I have cut are not part of answer so please see before writing
Attachments:
Similar questions