Question

if a+b+c=0 then prove that a^3+b^3+c^3=3abc​

Answer 1

Step-by-step explanation:

given--->a+b+c=0

to prove---> a³+b³+c³=3abc

proof--->We know,

a³+b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-c)

Putting a+b+c=0 on RHS, we get,

a³+b³+c³-3abc=0

⟹a³+b³+c³=3abc

Hence proved

Answer 2

✴Answer:

Refer the attachment hope it helps you!

since (a+b+c)=0 , the whole term gets cancelled and gives as 3abc /

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