Question

If a+b+c=0 then prove that (a+b)(b+c)(c+a)/abc=-1

Answer 1

Step-by-step explanation:

a+b+c=0

=> a+b = -c, b+c = -a, c+a = -b

LHS = (a+b)(b+c)(c+a)/abc

= (-c)(-a)(-b)/abc

= -abc/abc = -1 = RHS

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