Question

If √a+√b+√c=0 then prove that (a+b-c)2=4ab​

Answer 1

please see answer in the pic given below

mark it as a brainliest answer

Answer 2

Hence proved  $(a+b-c)^2=4ab$.

Step-by-step explanation:

Given : Expression $\sqrt{a}+\sqrt{b}+\sqrt{c}=0$

To prove : $(a+b-c)^2=4ab$

Proof :

$\sqrt{a}+\sqrt{b}+\sqrt{c}=0$

Write it as,

$\sqrt{a}+\sqrt{b}=-\sqrt{c}$

Squaring both side,

$(\sqrt{a}+\sqrt{b})^2=(-\sqrt{c})^2$

$(\sqrt{a})^2+(\sqrt{b})^2+2(\sqrt{a})(\sqrt{b})=c$

$a+b+2\sqrt{ab}=c$

$a+b-c=-2\sqrt{ab}$

Squaring both side,

$(a+b-c)^2=(-2\sqrt{ab})^2$

$(a+b-c)^2=4ab$

Hence proved.

#Learn more

Prove (a+b)^2=(a-b)^2+4ab

https://brainly.in/question/4695334