if a+b+c = 0 then prove that a(b-c)^3 + b(c-a)^3 + c(a-b)^3 = 0
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Answer:
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Step-by-step explanation:
By taking and solving LHS,
a(b-c)^3+b(c-a)^3+c(a-b)^3
=(ab)^3-(ac)^3+(bc)^3-(ab)^3+(ac)^3-(ab)^3
=0
So, LHS=RHS
Hence, Proved
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