Question

If (a+b+c)=0. Then prove that a cube +b cube +c cube = 3abc

Answer 1

hey mate here is your answer ✌♥✌♥

As we know that✔

a³ +b³+c³-3abc=(a+b+c)(a²+b²+c²-ab-bc-ac)❣

so as (a+b+c)=0✔

a³ +b³+c³-3abc=(0)(a²+b²+c²-ab-bc-ac)❣

a³ +b³+c³-3abc=0✔

a³+b³+c³=3abc❣

hence proved❤❤❤

hope it will be helpful to you ✔✔

mark me brainliest ✌✌✌