if a+b+c=0 then prove that a²/bc+b²/ca+c²/ab=3
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Step-by-step explanation:
a^2/bc+b^2/ca+c^2/ab
now take LCM which is abc
(a^3+b^3+c^3)/abc....(1)
but we know that a^3+b^3+c^3=3abc
now put that value in equation (1)
3abc/abc=3
3=3
hence,LHS=RHS
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