Math, asked by alimaamirkhan79, 2 days ago

if a+b+c= 0, then prove that a²/bc + b²/ca+c²/ab​

Answers

Answered by SupernovaMind
0

a+b+c=0

a+b=-c. …………….(1)

On cubing both sides

a^3+b^3+3a.b(a+b)=-c^3

a^3+b^3+c^3+3a.b(-c)=0

a^3+b^3+c^3=3a.b.c

Divide both side by a.b c

a^2/b.c+b^2/c.a+c^2/a.b=3 , Answer

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