Question

if a+b+c =0 then show that a^3+b^3+c^3=3(b+c)(c+a)(a+b)​

Answer 1

There is correction in your question Since a+b+c=0

-c=a+b

-b=c+a

-a=b+c

So, we know that for a+b+c=0

Then

a^3+b^3+c^3 =3abc

Hence,

a^3+b^3+c^3=-3(b+c)(c+a)(a+b)

Hope it helps you :-)

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