If a+b+c=0,then show that a3+b3+c3=3abc
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Step-by-step explanation:
We know a+b+c-3abc=(a^2 + b^2 + c^2 - ab - bc- ca). (0)(a2 + b2 + c2 - ab-bc- ca) = 0 proved
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a3+b3+c3=(a+b+c)(a2+b2+c2-ab-bc-ca)
a+b+c=0=a3+b3+c3=3abc
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