Question

If a + b + c = 0, then the value of a^2/a^2-bc+b^2/b^2-ca+c^2/c^2-ab is-:

Answer 1

Answer:

           2

Step-by-step explanation:

a + b + c = 0

⇒  a² + ab + ac = 0

⇒  a² - bc = -ab - bc - ca

Similarly,

    b² - ca  =  c² - ab  =  -ab - bc - ca

So the given expression is equal to

(a² + b² + c²) / (-ab - bc - ca).

Not finished yet...

a + b + c = 0

⇒  0 = (a + b + c)² = (a² + b² + c²) + 2(ab + bc + ca)

⇒  a² + b² + c² = -2(ab + bc + ca)

⇒  (a² + b² + c²) / (-ab - bc - ca)  =  2

Hope that helps!