Question

If a+b+c=0 then what is the value of a^3+b^3+c^3=0​

Answer 1

Answer:

ANSWER

Since, a

3

+b

3

+c

3

−3abc=(a+b+c)(a

2

+b

2

+c

2

−bc−ca−ab)

Given, a+b+c=0

∴a

3

+b

3

+c

3

−3abc=0

∴a

3

+b

3

+c

3

=3abc

Option B is correct

Answer 2

$Since, a {}^{3} +b {}^{3} +c {}^{3} −3abc \\ (a+b+c)(a {}^{2} +b {}^{2} +c {}^{2} −bc−ca−ab) \\Given, a+b+c=0 \\∴a {}^{3} +b {}^{3} +c {}^{3} −3abc=0 \\∴a {}^{3} +b {}^{3} +c {}^{3} =3abc$