if a+b+c=0 then what is the value of a3+b3+c3
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a3+b3+c3-3abc
=(a+b+c)(a2+b2+c2-ab-bc-ca)
=0. (since a+b+c=0)
so
a3+b3+c3-3abc=0
therefore,
a3+b3+c3=0
Hope this will help you.
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