Question

if a+b+c=0 where a, b and c are non zero real numbers then the value of
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Answer 1

Answer:

a+b+c+=0

Step-by-step explanation:

A = 5

B = 5

C = -10

SO, 5(A)+5(B)-10(C) = 0

Answer 2

Answer:

0.5 - 2abc/(a^4 +b^4 + c^4)

Step-by-step explanation:

(a+b+c) ^4 = a^4 + b^4 +c^4 + 12abc(a +b +c) + 4a^3(b+c) +4b^3(a + c) + 4c^3(a + b) + 6(a^2b^2 + a^2c^2 + b^2c^2)

Simplifying and assigning a+b+c=0 and taking b+c = -a, a+b = -c, a+c= -b

We get,

(a^2b^2 + b^2c^2 + c^2a^2) / (a^4 + b^4 + c^4) = 0.5 - 2abc/(a^4 + b^4 + c^4)