if a½+b½-c½=0then find the value of (a+b-c)²
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Step-by-step explanation:
√a+√b-√c=0
√a+√b=√c
squaring both side
(√a+√b)^2=(√c)^2
a+b=c
a + b - c = 0
squaring both side
(a+b-c)^2 = (0)^2
(a+b-c)^2 = 0
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