Question

if a+b+c= 0then prove that a cube+ b cube + c cube=3abc ​

Answer 1

Answer:

a+b+c = 0 (given)

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a³ + b³ + c³ = 3abc

a³ + b³ + c³ - 3abc = 0

(a+b+c) (a²+b²+c²-ab-bc-ca) = 0

0 x (a²+b²+c²-ab-bc-ca) = 0

0 = 0

LHS = RHS