Question

If A: B+C = 1:3, and B: C+A= 1:2, then find C: A+B=?
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Answer 1

A:B+C = 1x : 3x

A = x

B+C = 3x

B = 3x-C

B:C+A = 1y:2y

B = y

C+A = 2y

A= 2y-C.

x = 2y-C ( since x = A).........(1)

y = 3x - C (since y = B)............(2)

Solving (1) and (2)

We will get x = 3C/5

y = 4C/10

C : A+B

= C/ 3x-C+2y-C

= C/ 9C/5 + 8C/10

=C/ 26C/10

= 5:13