Question

If a+b+c=1, a sq. +b sq. +c sq. =9 and a cube+b cube+ c cube =1, find the value of 1/a+1/b1/c=?

Answer 1

Answer:

answer is 1 friend..

Step-by-step explanation:

a+b+c=1

a^2+b^2+c^2=9

a^3+b^3+c^3=1

(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)

1=9+2x

x= -4 = ab+bc+ca

a^3+b^3+c^3-3abc = (a+b+c) (a^2+b^2+c^2-ab-bc-ca)

1-3abc = 1 . (9+4)

abc = -4 .

1/a+1/b+1/c = bc+ca+ab/abc

-4/-4 = 1..

i hope u got it.. plz mark it as brainliest