Math, asked by sibaditya12345, 10 months ago

If a+b+c=1; a2+b+c=9; a+b+c=1, find 1/a+1b+1/c.​

Answers

Answered by deepanshushahi123
0

Step-by-step explanation:

1. a+b+c = 1

a = b + c

2. 2a + b + c = 9

2b + 2c +b +c=9

3 b+ 3 c = 9

b+ c = 3

a = 1/3

3. 1/a + b + 1/c

1/3 + 3-c + 1/ 3-b

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