If a+b+c=1; a2+b+c=9; a+b+c=1, find 1/a+1b+1/c.
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Step-by-step explanation:
1. a+b+c = 1
a = b + c
2. 2a + b + c = 9
2b + 2c +b +c=9
3 b+ 3 c = 9
b+ c = 3
a = 1/3
3. 1/a + b + 1/c
1/3 + 3-c + 1/ 3-b
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