Question

if a + b + C = 1 then find a+b by 1 -ab​

Answer 1

Answer:

sorry I don't now the answer it is a difficult quest

tion

Answer 2

Answer:

Let D= ∣∣∣∣∣∣∣∣1+a1111+b1111+c∣∣∣∣∣∣∣∣

∴D= (1+a)[(1+b)(1+c)−1]−1[(1+c)−1]+1[1−1−b]

∴D=ac+ab+bc+abc

Since, a1+b1+c1=0

∴ab+bc+ac=0

Hence, D=abc