if a+b+c=10,ab+bc+ca=25,find the value of a2+b2+c2,
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Answered by
1
Answer:
answer is 50
Step-by-step explanation:
Given,
a+b+c=10 and ab+bc+ca=25
We know,
(a+b+c)
2
=(a
2
+b
2
+c
2
)+2(ab+bc+ca)
Thus,
(a+b+c)
2
=(a
2
+b
2
+c
2
)+2(ab+bc+ca)
=>10
2
=a
2
+b
2
+c
2
+2(25)
=>100−50=a
2
+b
2
+c
2
=>a
2
+b
2
+c
2
=50
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