If a+b+c=11 and ab+ bc+
ca=15 then a^2+ b^2+c^2 =
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Solution :
⇛a + b + c = 11
⇛ab + bc + ca = 15
⇛a² + b² + c² = ???
›(a+b+c)² = a² + b² + c² +2ab+2bc+2ca
›(a+b+c)² - (2ab + 2bc + 2ca) = a²+b²+c²
›› a² + b² + c² = (11)² -2(15)
›› a² + b² + c² = 121 - 30
›› a² + b² + c² = 91
Hence
- value of a² + b² + c² = 91
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