If a + b + c = 11 and ab + bc + ca = 27, then find a² + b² + c²
Answers
Answered by
4
Answer:
a²+b²c²= a+b+c+2ab 2bc+2ca
= 11+2(ab+BC+ca)
= 11+2×27
=65
Answered by
1
Answer:71
Step-by-step explanation:
By formula,
(a+b+c)^2=a^2+b^2+c^2+2(ab+bc+ca)
(11)^2=a^2+b^2+c^2+2×27
121=a^2+b^2+c^2+54
121-54=a^2+b^2+c^2
71=a^2+b^2+c^2
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