Question

If a+b+c=11 and ab+bc+ca=36 find the value of a2+b2+c2​

Answer 1

Here's your answer pal

A+b+c=a^2b^2+c^2+2(ab+bc+ac)

11^2=a^2+b^2+c^2+36*2

a^2+b^2+c^2=121-72

=49

Answer 2

Answer:

Here is ur solution

Step-by-step explanation:

Given that,a+b+c=11 (eqn1)

and ab+bc+ca=36 (eqn2)

Now ,Squaring eqn 1

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca

(11)²=a²+b²+c²+2(36)

121-72=a²+b²+c²

49=a²+b²+c²

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