Math, asked by suvid60, 1 year ago

if a+b+c=12 a^2+b^2+c^2=100 find ab+bc+ca​

Answers

Answered by rohit2014
13

Answer:

(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac

(12)^2=100+2(ab+bc+ac)

144-100=2(ab+bc+ac)

44/2=ab+bc+ac

22=ab+bc+ac

Step-by-step explanation:

hence ab+bc+ac=22

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Answered by Anonymous
3

⏩Hey mate❤

given here

a+b+c= 12. ...(1)

And

a²+b²+c²= 100. ...(2)

Find here

ab+bc+ca=

Solution:--

we know that

(a+b+c)²=a²+b²+c²+2ab+2bc+2ca

put value by (1) and (2)

we get,

(12)²=(100)+2(ab+bc+ca)

=>144-100=2(ab+bc+ca)

=>44/2= (ab+bc+ca)

=>(ab+bc+ca)=22

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