if a+b+c=12 a^2+b^2+c^2=100 find ab+bc+ca
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Answered by
13
Answer:
(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ac
(12)^2=100+2(ab+bc+ac)
144-100=2(ab+bc+ac)
44/2=ab+bc+ac
22=ab+bc+ac
Step-by-step explanation:
hence ab+bc+ac=22
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Answered by
3
⏩Hey mate❤
given here
a+b+c= 12. ...(1)
And
a²+b²+c²= 100. ...(2)
Find here
ab+bc+ca=❓❓
Solution:--
we know that
(a+b+c)²=a²+b²+c²+2ab+2bc+2ca
put value by (1) and (2)
we get,
(12)²=(100)+2(ab+bc+ca)
=>144-100=2(ab+bc+ca)
=>44/2= (ab+bc+ca)
=>(ab+bc+ca)=22
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